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  • vnmanpower's Avatar
    Today, 08:05
    Vietnam Manpower JSC is one of leading recruitment agency from Vietnam supplying labors to abroad. Especially, we have been exporting thousands of workers to Saudi Arabia, Quatar, UAE, Kuwait, Oman, Malaysia, Brunei, Czech, Slovakia, Taiwan, Libya….with many type of categories : Textile – Garment, Mechanic, Electricity – Electronic, Packing, Construction, Nurse and Health Care, Agriculture, Hotel and restaurant, Driver… Vietnamese construction worker is one of vital job sectors that Vietnam Manpower JSC is focusing. Being equipped with highly- professional levels, along with hard-working, diligent and inquisitive spirits, Vietnamese construction always meets the most strict requirements of employers. Through meticulous and careful selection process, Vietnam Manpower JSC seems to be dominant in supplying human resources in this labor segment. We have been recruited hundreds of construction workers to FINO company or QD-SBG corporation in Quatar and other large companies… ...
    0 replies | 46 view(s)
  • PWASS's Avatar
    24th Jan '15, 08:27
    Mira It's hard to tell, but it looks like it's driving the chain at slow speed through a gearbox, this would indicate that it's not driving the hydraulics. There must be a small hydraulic unit in the machine, it might not be obvious because sometimes the electric drive motor is submerged under the oil in the reservoir. Follow the pipes that are connected to the cylinders, they should lead you back to some valves and then back the hydraulic unit. Do you know what the hydraulic pressure should be?
    16 replies | 1227 view(s)
  • FLM's Avatar
    24th Jan '15, 01:11
    Yep I was looking at that equation and went on to page 438 where they have the simplified eqn which I had been using anyway. I thought surely he can't mean that huge eqn!! Ok leave this wit me as I don't have all the required info but hopefully will early next week..... And yes after all your help I will send you a 6 pack of the black stuff!!
    9 replies | 314 view(s)
  • mira's Avatar
    23rd Jan '15, 20:57
    Hi, Thank you for your replies to my problem. I have uploaded a video of our machine. http://youtu.be/DwTnvzkv3bY Please advice me what kind of hydraulic system is working in this machine. Is the blue colored motor a part of hydraulic assembly? I want to find out that if the hydraulic assembly has enough pressure or not. Thank you all,
    16 replies | 1227 view(s)
  • Lochnagar's Avatar
    23rd Jan '15, 20:00
    Have you looked at page 437 of the book I posted a link to - see above? As I also said in my earlier posting - you need to preload the bolt to about 75% of the proof strength. So the axial load on the bolt needs to equivalent to 75% of the proof strength. So for a M6 x 1P the cross sectional area is defined (not as pi D^2 / 4) - but as defined on page 412 - see the equations at the foot of the table. So you will see that the XSA = 20.1mm^2. So 6730/20.1 = 335N/mm^2. And 335/450 = 75%. If you don't like the more complex equation I have detailed on page 437 - then you can use T=0.2 x F x D - though I have to say I prefer the full equation on page 437 - since it deals with washer diameter too. However, if you use T = 0.2 x 6730 x (6/1000) = 8Nm. If you use the full equation on page 437 - you get 8.5Nm. Hope this helps - and by the way I will have a pint of Guiness:)
    9 replies | 314 view(s)
  • FLM's Avatar
    23rd Jan '15, 18:22
    Hey sorry but I am still not seeing where you are getting 8.5 from? You are using T=KFd?
    9 replies | 314 view(s)
  • Lochnagar's Avatar
    23rd Jan '15, 18:05
    Hi FLM, The equation to compute the 8.5Nm - I use is from Shigley - which is the "Engineers Bible" - see the link below - you will see the equation I use is at the bottom of page 437. There are a few other expressions you need from Chapter 8 of this book - and so I have brought everything together and made my own Excel Spreadsheet. https://books2all.files.wordpress.com/2013/12/shigley-machine-design-9th-edition.pdf The bolt clamps the tube - which exerts a radial force of 12136N. The tangential force is the friction force resisting rotation - and that is the friction coefficient times the normal (or radial force). (If you think about a block you are trying to push across a desk - the resistance to motion is the coefficient of friction between the two surfaces times the weight of the block - so the friction force is perpendicular to the normal or "weight force"). Hence we have 12136 x 0.3 = 3640N. So the force on the top of the handlebar is 12136N - and there must be an...
    9 replies | 314 view(s)
  • FLM's Avatar
    23rd Jan '15, 17:16
    Ok this is appears to be on the lines of what I am looking for. I am confirming the bolt details but yes as far as I know it is an M7 bolt. I dont as of yet know the pitch or thread quantity. The materials used are steel - i am awaiting confirmation of the grades of steel. The CoF for steel is 0.2. Your proof strength I assume is from a table? I will get this once I get the bolt specs. I am not sure where you get 8.5Nm from (something simple I am missing). You then work out clamping force - what eqn are you using there? F=T/cD? If you could explain this paragraph below and where you get the equations and figures from that would be great:
    9 replies | 314 view(s)
  • Lochnagar's Avatar
    23rd Jan '15, 16:31
    Hi FLM, You say the bolt is 7mm - which notionally appears an unusual size to me - because the "standard sizes" are M5, M6, M8, M10. I am not saying it is not an M7 - all I am saying is that is not a "standard size" - therefore it might be worth double checking the bolt shank/thread diameter. If the bolt is a stainless bolt M6 x 1.0Pitch (Grade A4-70) - this will have a proof strength of 450N/mm^2 - so we would typically tighten it to 75% of the proof strength - which roughly computes to 8.5/9Nm. (It varies a little depending on bolt washer diameter). So at 8.5Nm tightening torque - this equates to a clamping force of 6730N. So if you look at the clamping bracket now - to get equilibrium - we have 6730 x 51.7 - P x 28.67 = 0 (Where P is the clamp force on the handle bar). P = 12136N. You haven't stipulated the material of the handlebar - or the clamp - but lets assume it is aluminium. The coefficient of friction for aluminium to aluminium - is roughly 0.3 - though higher...
    9 replies | 314 view(s)
  • Dovile's Avatar
    23rd Jan '15, 16:16
    Carbolite has more than 75 years' experience in thermal engineering and have developed a product range with a global reputation for quality & performance with more than 70% of sales derived from Export markets. Today, Carbolite equipment has become the standard against which other heat processing equipment is measured with a product range which includes both laboratory chamber/box furnaces & laboratory tube furnaces to 1800°C. Job Description Due to continued growth and development of the business they now require a high calibre, Engineering Project Manager to support their growth plans. As the Project Manager you will be influential in taking ownership and responsibility for the engineering and managing all aspects of a project from design to customer delivery including: quotation; product engineering; logistics; installation and commissioning. This is a great opportunity for a talented individual to design and develop market leading products, creating a culture of...
    0 replies | 95 view(s)
  • Bizzar's Avatar
    23rd Jan '15, 15:28
    My advise is save uncompressed and convert after or do Bitmaps and combine them in Movie Maker... to be honest I had the same problem when I tried to compress in SW.
    5 replies | 1909 view(s)
  • teja's Avatar
    23rd Jan '15, 14:20
    sir i am having doubt on loadings on shaft.which is of slag transfer car which moves on a rail now there is a shaft which is having two wheels and two bearings(axle box) at ends and gear box at middle and my doubt is where the entire body weight act and and scrap weight i should add and where reaction forces act? i will be glad if you reply thanks
    2 replies | 829 view(s)
  • teja's Avatar
    23rd Jan '15, 14:06
    sir i am having doubt on loadings on shaft.which is of slag transfer car which moves on a rail now there is a shaft which is having two wheels and two bearings(axle box) at ends and gear box at middle and my doubt is where the entire body weight act and and scrap weight i should add and where reaction forces act? i will be glad if you reply thanks
    9 replies | 314 view(s)
  • FLM's Avatar
    23rd Jan '15, 12:49
    Hi lochnagar Sorry to be a bit more clearer I have attached a proper picture of the design. I understand exactly what you are saying and I agree - the problem is most likely a manufacturing/assembly issue. What I am trying to do is find and equation to compare the force of 1 bolt versus 2 or 4.
    9 replies | 314 view(s)
  • Lochnagar's Avatar
    23rd Jan '15, 10:56
    Just so that we are all on the same page about what we are talking about here "in general terms" – please refer to the pictures in the hyperlink below of two fundamentally different types of coupling here:- There is a one-piece clamping collar – which has been “weakened” by cutting partially through the wall on the opposite side – however, as you will see in the pictures in the link below – they can have one or more bolts to clamp them. There is a two-piece clamping collar – which has been made by cutting completely through the wall on both sides – however, as you will see in the pictures in the link below – they can have two or more bolts to clamp them. http://www.ondrives.com/collars-and-clamps
    9 replies | 314 view(s)
  • Dovile's Avatar
    23rd Jan '15, 10:03
    Aircraft Installation Fitter BAE Systems Military Air & Information are currently recruiting for a number of skilled Aircraft Installation Fitters to work on a permanent basis across Warton Unit, Lancashire. Aircraft fitters are employed to conduct mechanical tasks across a wide range of products including Typhoon and Hawk covering the full production lifecycle from detail manufacturing, minor and major assemblies, final assembly to acceptance and delivery to customers. Applicants must have served a recognised apprenticeship, have a deep understanding of mechanical work and should be able to carry out the various tasks performed in the aircraft and support industry. As an Aircraft Installation Fitter your main responsibilities will involve:
    0 replies | 2280 view(s)
  • Bizzar's Avatar
    22nd Jan '15, 22:30
    my advise is to get one of dell workstations. maybe are not cheap but are designed for CAD. workstation 4800 does the job, but my opinion is to use powetful PC. Even if you are using solidworks for design simple parts, in the future you will have to work with large assemblies or do rendered animations.
    5 replies | 1113 view(s)
  • FLM's Avatar
    22nd Jan '15, 17:35
    Hi Folks I am looking for some help in a calculation if possible. I am looking at a bike design where the handlebars are clamped in place in the stem using only 1 bolt - see the picture below for an example. http://i.ebayimg.com/00/s/MTE5OFgxNjAw/z/rdgAAOxyrYFR2wbP/$(KGrHqF,!k8FHQwpchTzBR2wbP!Now~~60_35.JPG There has been issues with the handle bars slipping forward when in use. I think that this is a manufacturing problem and not a design issue as this type of stem with one bolt is quite common.
    9 replies | 314 view(s)
  • jhinkis47's Avatar
    22nd Jan '15, 17:02
    Mechanical Design Engineer Qualification:- Bachelor in Engineering from UoP (2014) Industrial Experience:- Project at Bharat Forge Ltd. Pune, India for 1 year dealing with HRC trays and carried out effective modelling and analysis of trays using ProE and ANSYS respectively. Working with an Furniture Equipment manufacturing small scale company named Total Impex as an Design Engineer on CATIA V5 as a modelling software, sucessfully completed two projects at company. CAD qualifications:- SolidWroks, ProE, CATIA V5, AutoCAD. Designing and Researching about the products and working on their efficieny and asthetic levels to make the product functionally excellent. Researching on exsisting equipments or products finding out different ways to create or modify and make it more efficent and less costly. Basically, working on design and modelling them and creating a best output is my superior priority
    0 replies | 165 view(s)
  • Dzevad's Avatar
    22nd Jan '15, 15:31
    Thank you.
    1 replies | 3015 view(s)
  • idir's Avatar
    22nd Jan '15, 11:57
    is there someone who use Flux2D Cedrat :confused:
    0 replies | 83 view(s)
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