Conversion of Specific fuel Consumptions

[hemcrop]

Dear All,

I have Data Sheet of a Diesel Engine of capacity 1650KVA/ 1320KW. The fuel Consumption of Engine is given in terms of g/kWh for specific loads as shown below.

Specific Fuel Consumption (be) - 100% FSP - 193 g/kWh
Specific Fuel Consumption (be) - 75% FSP - 194 g/kWh
Specific Fuel Consumption (be) - 50% FSP- 201 g/kWh
Specific Fuel Consumption (be) - 25% FSP- 228 g/kWh

please tell me how to convert above consumptions values from g/kWh to liters.
Is there any formula involved to convert it/

Cheers,

Hemcrop

[mihai]

Hy!

You can use this formula:
CI=c x P x 1/ro

where: c - specific consumption (g/kWh)
P - power (kW)
ro - fuel density (kg/m3)
Your result CI (fuel consumption in time) will be in m3/h. (x 1000 for liters/h)

Cheers,
Mihai

[hemcrop]

P - is power for a specific load (25%, 50%, 75%, 100%), in your case, 100% is 1320kW.

So, your consumption for one hour (if, for example, you are using gasoline ro=835kg/m3):

CI (100%) = 0,193kg/kWh x 1/835kg/m3 x 1320kW = 0,305 m3/h = 305 l/h

cheers,
Mihai

Thanks A lot mihai. This Definitely going to help me a lot.

Cheers
Hemcrop

[mihai]

P - is power for a specific load (25%, 50%, 75%, 100%), in your case, 100% is 1320kW.

So, your consumption for one hour (if, for example, you are using gasoline ro=835kg/m3):

CI (100%) = 0,193kg/kWh x 1/835kg/m3 x 1320kW = 0,305 m3/h = 305 l/h

cheers,
Mihai

[brijs]

Hi all,
Thanks mihai, The formula CI=c x P x 1/ro is absolutely correct.

[leenko]

What is the RO of Diesel?