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Thread: Conversion of Specific fuel Consumptions

  1. #1

    Conversion of Specific fuel Consumptions

    Dear All,

    I have Data Sheet of a Diesel Engine of capacity 1650KVA/ 1320KW. The fuel Consumption of Engine is given in terms of g/kWh for specific loads as shown below.

    Specific Fuel Consumption (be) - 100% FSP - 193 g/kWh
    Specific Fuel Consumption (be) - 75% FSP - 194 g/kWh
    Specific Fuel Consumption (be) - 50% FSP- 201 g/kWh
    Specific Fuel Consumption (be) - 25% FSP- 228 g/kWh

    please tell me how to convert above consumptions values from g/kWh to liters.
    Is there any formula involved to convert it/

    Cheers,

    Hemcrop



  2. #2

    Re: Conversion of Specific fuel Consumptions

    Hy!

    You can use this formula:
    CI=c x P x 1/ro

    where: c - specific consumption (g/kWh)
    P - power (kW)
    ro - fuel density (kg/m3)
    Your result CI (fuel consumption in time) will be in m3/h. (x 1000 for liters/h)

    Cheers,
    Mihai

  3. #3

    Re: Conversion of Specific fuel Consumptions

    Quote Originally Posted by mihai
    P - is power for a specific load (25%, 50%, 75%, 100%), in your case, 100% is 1320kW.

    So, your consumption for one hour (if, for example, you are using gasoline ro=835kg/m3):

    CI (100%) = 0,193kg/kWh x 1/835kg/m3 x 1320kW = 0,305 m3/h = 305 l/h

    cheers,
    Mihai
    Thanks A lot mihai. This Definitely going to help me a lot.

    Cheers
    Hemcrop

  4. #4

    Re: Conversion of Specific fuel Consumptions

    P - is power for a specific load (25%, 50%, 75%, 100%), in your case, 100% is 1320kW.

    So, your consumption for one hour (if, for example, you are using gasoline ro=835kg/m3):

    CI (100%) = 0,193kg/kWh x 1/835kg/m3 x 1320kW = 0,305 m3/h = 305 l/h

    cheers,
    Mihai

  5. #5

    Re: Conversion of Specific fuel Consumptions

    Hi all,
    Thanks mihai, The formula CI=c x P x 1/ro is absolutely correct.

  6. #6
    What is the RO of Diesel?

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